Stuck with raw unicode literals

[Chitrank Dixit]

Hello Python developers

I am working on Python Porting 2.7 >=3.3 . unicode literals will be fine
but still raw unicode literals is an issue (ur' '). I have found the
solution in six module.

This is the solution

original python 2.7 code
ur'Pythondev'

using six module for py 2.7>=3.3
six.u(r'Pythondev')

Does my solution is okay or something else is needed to do I am very
confused with this.


*Regards
*
*Chitrank Dixit
*
*IIPS-DAVV
*
*Indore (M.P.) , India *
*MCA
*
*trackleech.blogspot.in*

[Lennart Regebro]

Post by Chitrank Dixit
Hello Python developers
I am working on Python Porting 2.7 >=3.3 . unicode literals will be fine but
still raw unicode literals is an issue (ur' '). I have found the solution in
six module.
This is the solution
original python 2.7 code
ur'Pythondev'
using six module for py 2.7>=3.3
six.u(r'Pythondev')
Does my solution is okay or something else is needed to do I am very
confused with this.

Well the first question is why you need a raw unicode literal in the
first place?

Raw string literals simply interpret escape sequences literally, so
that '\0x00' is interpreted as a four character string, while in
normal strings it's interpreted as a once character string.

Unicode literals are weird beasts, where most backslash escape
sequences are interpreted literally, but not the Unicode escape
sequences, so '\0x00' is four characters, but '\u0000' is one.

The simplest way to handle it might simply to be to escape the
backslashes, ie change ur'\0x57bla\foo' to u'\\0x57bla\\foo'

//Lennart